NTA is a Nigerian government-owned and partly commercial broadcaster that was inaugurated in 1977, at inauguration it had a monopoly on television broadcasting in the country.
The NTA runs the biggest television network in Africa with stations in several parts of Nigeria. Has NTA Recruitment 2019 started? This is a question lots of our readers have been asking us. Today, we have decided to cover every aspect of the National Television Authority Recruitment. NTA is currently recruiting graduates and non-graduates into various vacant positions in the organization.
NTA Recruitment 2019 Requirements
The requirements for this recruitment exercise is stated below;
Possession of OND, NCE, HND and B.Sc., in any discipline from any recognized Institution.
Computer literacy will be an added advantage.
All Applicants must possess five (5) credits in SSCE/WASSCE, including English Language and Mathematics at a sitting, or six (6) credits at not more than two (2) sittings, including English Language and Mathematics.
All Applicant Must Possess NYSC discharge certificates.
Applicants must not be above 35 years.
Important Points to Note on NTA Recruitment
There are a lot of things you should take into consideration when applying for NTA Recruitment 2019. Getting the right information at the right time is very important which means you need to be visiting NTA Portal on a regular basis.
Take note of the following information if you wish to be successful in getting employed by NTA.
Have all the necessary credentials
Scan and Upload your Credentials on www.nta.ng
NTA Shortlisted Candidates will be published shortly after
Don’t pay anyone who claims he can help you get a Job in NTA.
How to Apply for NTA Recruitment 2019
To apply, Visit www.nta.ng or keep visiting this website to stay updated on the application procedures.
If you need more updates about NTA Recruitment 2019, kindly provide us with your email address in the comment section below and we will reach out to you
https://www.hotfrom9ja.com/2019/06/nta-2019-job-recruitment.html?m=1
